Mensuration Formula Sheet - IBPS PO Prelims
Chapter Overview: Mensuration is a high-scoring topic in the Quantitative Aptitude section of the IBPS PO (Probationary Officer) Prelims examination. This comprehensive LibreTexts-style reference chapter covers essential 2D (Plane) and 3D (Solid) geometry concepts, surface area formulas, volume equations, and problem-solving shortcuts. Master these core formulas to improve speed and accuracy during speed-based competitive exams.
1. Exam Context & PYQ Weightage Analysis
In the IBPS PO Prelims Quantitative Aptitude section, Mensuration typically accounts for 1 to 3 direct questions. Furthermore, concepts of 2D and 3D mensuration frequently appear in Data Interpretation (DI) sets, particularly Caselet DI and Mensuration-based Radar/Bar charts.
NTA / IBPS Exam Pattern Trends: Questions usually involve a combination of two shapes (e.g., a sphere melted into a cylinder, or a circle inscribed in a square) or ratio-based parameter variations. Memorizing direct geometric relations and efficiency in calculation are essential for attempting these questions within the tight sectional timing.
2. Chapter 1: 2D Shapes (Plane Mensuration)
2D Mensuration deals with boundary lengths (perimeter/circumference) and surface coverage (area) of flat two-dimensional figures.
2.1 Triangles
For any triangle with base \(b\) and height \(h\):
\[A = \frac{1}{2} \times b \times h\]
When all three sides \(a\), \(b\), and \(c\) are known, use Heron's Formula:
\[A = \sqrt{s(s-a)(s-b)(s-c)}\]
where the semi-perimeter \(s = \frac{a+b+c}{2}\).
For an Equilateral Triangle with side length \(a\):
- Area: \[A = \frac{\sqrt{3}}{4} a^2\]
- Height: \[h = \frac{\sqrt{3}}{2} a\]
2.2 Quadrilaterals
- Rectangle: Area \(= l \times b\), Perimeter \(= 2(l + b)\), Diagonal \(= \sqrt{l^2 + b^2}\)
- Square: Area \(= a^2\), Perimeter \(= 4a\), Diagonal \(= a\sqrt{2}\)
- Parallelogram: Area \(= b \times h\)
- Rhombus: Area \(= \frac{1}{2} \times d_1 \times d_2\) (where \(d_1\) and \(d_2\) are diagonal lengths)
- Trapezium: Area \(= \frac{1}{2}(a + b) \times h\) (where \(a\) and \(b\) are parallel sides)
2.3 Circles, Arcs & Sectors
For a circle of radius \(r\):
- Area: \[A = \pi r^2\]
- Circumference: \[C = 2\pi r\]
- Arc Length (\(l\)) subtending angle \(\theta\) at center: \[l = \frac{\theta}{360^\circ} \times 2\pi r\]
- Area of Sector: \[A = \frac{\theta}{360^\circ} \times \pi r^2 = \frac{1}{2} \cdot l \cdot r\]
3. Chapter 2: 3D Shapes (Solid Mensuration)
3D Mensuration covers volumetric capacity, Curved/Lateral Surface Area (CSA/LSA), and Total Surface Area (TSA) of three-dimensional solids.
3.1 Cubes & Cuboids
Cube (Edge length \(a\)):
- Total Surface Area (TSA): \[6a^2\]
- Curved / Lateral Surface Area (LSA): \[4a^2\]
- Volume: \[a^3\]
- Space Diagonal: \[a\sqrt{3}\]
Cuboid (Length \(l\), Width \(b\), Height \(h\)):
- TSA: \[2(lb + bh + hl)\]
- LSA (Area of 4 walls): \[2(l + b)h\]
- Volume: \[l \times b \times h\]
- Space Diagonal: \[\sqrt{l^2 + b^2 + h^2}\]
3.2 Cylinders & Cones
Right Circular Cylinder (Radius \(r\), Height \(h\)):
- Curved Surface Area (CSA): \[2\pi rh\]
- Total Surface Area (TSA): \[2\pi r(r + h)\]
- Volume: \[\pi r^2 h\]
Right Circular Cone (Radius \(r\), Height \(h\)):
- Slant Height (\(l\)): \[l = \sqrt{r^2 + h^2}\]
- CSA: \[\pi rl\]
- TSA: \[\pi r(r + l)\]
- Volume: \[\frac{1}{3}\pi r^2 h\]
3.3 Spheres & Hemispheres
Sphere (Radius \(r\)):
- Surface Area: \[4\pi r^2\]
- Volume: \[\frac{4}{3}\pi r^3\]
Hemisphere (Radius \(r\)):
- Curved Surface Area (CSA): \[2\pi r^2\]
- Total Surface Area (TSA): \[3\pi r^2\]
- Volume: \[\frac{2}{3}\pi r^3\]
4. Frequently Asked Questions (People Also Ask)
Q1: What is the weightage of Mensuration in IBPS PO Prelims?
Mensuration directly accounts for 1-3 standalone questions in IBPS PO Prelims. Additionally, 3D shape concepts frequently feature in Data Interpretation (DI) caselets.
Q2: What is the difference between Lateral Surface Area (LSA) and Total Surface Area (TSA)?
LSA (or CSA) calculates the area of the outer curved/side faces excluding top and bottom bases. TSA includes LSA plus the surface area of both base caps.
Q3: How do you solve recasting or melting solid object problems in Mensuration?
When one 3D object is melted or recast into another shape, the total volume remains constant. Equate the initial volume to the final volume to solve for missing dimensions.
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